s^2+3sj-28j^2=0

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Solution for s^2+3sj-28j^2=0 equation: 


Simplifying
s2 + 3sj + -28j2 = 0

Reorder the terms:
3js + -28j2 + s2 = 0

Solving
3js + -28j2 + s2 = 0

Solving for variable 'j'.

Factor a trinomial.
(-7j + -1s)(4j + -1s) = 0


Subproblem 1
Set the factor '(-7j + -1s)' equal to zero and attempt to solve:

Simplifying
-7j + -1s = 0

Solving
-7j + -1s = 0

Move all terms containing j to the left, all other terms to the right.

Add 's' to each side of the equation.
-7j + -1s + s = 0 + s

Combine like terms: -1s + s = 0
-7j + 0 = 0 + s
-7j = 0 + s
Remove the zero:
-7j = s

Divide each side by '-7'.
j = -0.1428571429s

Simplifying
j = -0.1428571429s

Subproblem 2
Set the factor '(4j + -1s)' equal to zero and attempt to solve:

Simplifying
4j + -1s = 0

Solving
4j + -1s = 0

Move all terms containing j to the left, all other terms to the right.

Add 's' to each side of the equation.
4j + -1s + s = 0 + s

Combine like terms: -1s + s = 0
4j + 0 = 0 + s
4j = 0 + s
Remove the zero:
4j = s

Divide each side by '4'.
j = 0.25s

Simplifying
j = 0.25s
Solution
j = {-0.1428571429s, 0.25s}

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